Write an equation in point-slope form of the line that has a slope of 1/2 and passes through the point (5,-2)
sorry, ive been working all night and im super tired hence my name
Hi Sleepy, thanks for using Jiskha! Please note that algebra is not spelled "algeabra". I have corrected the spelling in this post.
Write an equation in point-slope form of the line that has a slope of 1/2 and passes through the point (5,-2) >>
(y+2)=.5(x-5)
(5, -2), (x, y). m = 1/2.
m = (y+2)/(x-5) = 1/2,
2(y+2) = (x-5),
(y+2) = 1/2(x-5).
To write the equation of the line using the point-slope form, we need the slope of the line and one point that lies on the line.
Given that the slope is 1/2 and the point is (5, -2), we can substitute these values into the point-slope form:
y - y1 = m(x - x1)
Where:
m is the slope
(x1, y1) is the given point
Substituting the values into the equation:
y - (-2) = 1/2(x - 5)
Simplifying:
y + 2 = 1/2(x - 5)
This is the equation of the line in point-slope form that has a slope of 1/2 and passes through the point (5, -2).