If 3.15 Of Mercury Oxide Is Thermaly Decompose, What Mass Of Mercury That Will Be Produced?
0.0987 Of Mercury
Your answer is not right.
To determine the mass of mercury produced when 3.15 grams of mercury oxide decomposes, we need to know the molar mass of mercury oxide and the balanced chemical equation for the decomposition reaction.
Let's start by finding the molar mass of mercury oxide. The formula for mercury oxide is HgO. The atomic mass of mercury (Hg) is approximately 200.59 grams per mole, and the atomic mass of oxygen (O) is approximately 16.00 grams per mole.
The molar mass of mercury oxide can be calculated by adding the atomic masses of mercury and oxygen:
Molar mass of HgO = (1 * atomic mass of Hg) + (1 * atomic mass of O) = 200.59 + 16.00 = 216.59 grams per mole.
Next, we need to determine the balanced chemical equation for the thermal decomposition of mercury oxide:
2HgO -> 2Hg + O2.
From the balanced equation, we can see that 2 moles of mercury oxide decompose to produce 2 moles of mercury. Therefore, the ratio of mercury oxide to mercury is 1:1.
To calculate the mass of mercury produced when 3.15 grams of mercury oxide decomposes, we can use the following steps:
1. Convert the given mass of mercury oxide to moles:
Moles of HgO = Mass of HgO / Molar mass of HgO.
Moles of HgO = 3.15 grams / 216.59 grams per mole.
2. Determine the moles of mercury produced by using the 1:1 ratio:
Moles of Hg = Moles of HgO.
3. Convert the moles of mercury to mass:
Mass of Hg = Moles of Hg * Molar mass of Hg.
By following these steps, you can calculate the mass of mercury that will be produced.