Math

The bearing of x from y is 070 and the bearing of z from y is 160, where x, y, and z are three points in the plane .if y is equidistant from x and z, find the bearing of z from x

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  1. I need an answer to the question

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  2. I assume that those are compass bearings, clockwise from North.
    In that case x is one unit away from y at the origin, 20 degrees above the x axis (East)
    z is 160 - 90 = 70 degrees below the x (East axis), again one unit of distance.
    Lo and behold, the angle xyz is 20 + 70 = 90 degrees
    That means the triangle angles at x and z are each 45 degrees, which might be useful.
    call the intersection of xz with the x axis w
    then y w x = 180 - 45 - 20 = 115
    that is 115 - 90 = 25 deg clockwise from north
    so zw direction is 25
    so xz direction = 180 + 25 = 205
    about SSW

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  3. I need the answer

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  4. 315

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  5. 180 less 90 is 90 therefore the triangle is issoscless hence 90 divided by 2 gives 45 also 360 less 45 is 315 final answer

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  6. The bearing of q from p is 180°+70°=250°

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