Create an abstract geometric representation. Display two points, point X and point Z, which are equidistant from point Y in a plane. Indicate with dashed lines and arrows the bearings: from point Y to X and from point Y to Z, with angles of roughly 070 and 160 degrees respectively. No numerical or textual notations should be included in the image. Use soft colors for the background and vivid colors for the points and bearing lines.

The bearing of x from y is 070 and the bearing of z from y is 160, where x, y, and z are three points in the plane .if y is equidistant from x and z, find the bearing of z from x

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315

ANSWER PLEASE

180 less 90 is 90 therefore the triangle is issoscless hence 90 divided by 2 gives 45 also 360 less 45 is 315 final answer

The bearing of q from p is 180°+70°=250°

180+70 =250

180 less 90 is 90 therefore the triangle is issoscless hence 90 divided by 2 gives 45 also 360 less 45 is 315 final answer

To find the bearing of point z from point x, we need to determine the angle formed between the line connecting x and z and the north direction.

Given:
- The bearing of x from y is 070. This means that the angle formed between the line connecting y and x and the north direction is 70 degrees clockwise.
- The bearing of z from y is 160. This means that the angle formed between the line connecting y and z and the north direction is 160 degrees clockwise.

Since y is equidistant from x and z, we can conclude that the angle formed between the line connecting x and y and the line connecting y and z is 180 degrees (a straight line).

To find the bearing of z from x, we need to determine the angle formed between the line connecting x and z and the north direction. We can use the angle between y and z (160 degrees) and subtract it from the angle between y and x (70 degrees).

The calculation would be as follows:
Angle of z from x = Angle of z from y - Angle of x from y

Angle of z from x = 160 - 70 = 90 degrees.

Therefore, the bearing of z from x is 090.

I assume that those are compass bearings, clockwise from North.

In that case x is one unit away from y at the origin, 20 degrees above the x axis (East)
z is 160 - 90 = 70 degrees below the x (East axis), again one unit of distance.
Lo and behold, the angle xyz is 20 + 70 = 90 degrees
That means the triangle angles at x and z are each 45 degrees, which might be useful.
call the intersection of xz with the x axis w
then y w x = 180 - 45 - 20 = 115
that is 115 - 90 = 25 deg clockwise from north
so zw direction is 25
so xz direction = 180 + 25 = 205
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