solve system using substitution. 2x+2y=38 y=x+3
plz help
2x+2y=38
y=x+3
2x + 2(x + 3) = 38
4x + 6 = 38
4x = 32
x = 8
Take it from there.
She took 6 from the left side and 6 from the right side to even it out
To solve the system of equations using the substitution method, you need to isolate one variable in one equation and substitute it into the other equation. Follow these steps:
Step 1: Start with the given equations:
Equation 1: 2x + 2y = 38
Equation 2: y = x + 3
Step 2: Choose one equation to isolate a variable. Let's isolate "y" in Equation 2 since it is already in terms of "x."
y = x + 3
Step 3: Substitute the expression for "y" from Equation 2 into Equation 1 to eliminate "y."
2x + 2(x + 3) = 38
Step 4: Simplify and solve for "x."
2x + 2x + 6 = 38
4x = 32
x = 8
Step 5: Substitute the value of "x" back into Equation 2 to find the value of "y."
y = 8 + 3
y = 11
Step 6: Check the solution by substituting the values of "x" and "y" into both original equations.
Equation 1: 2(8) + 2(11) = 16 + 22 = 38 (satisfied)
Equation 2: 11 = 8 + 3 = 11 (satisfied)
Therefore, the solution to the system of equations is x = 8 and y = 11.