math

I recently learned that in order to graph any trig function you need to factor the period out of the phase shift. Can someone explain why? I think this has something to do with the multiple x intercepts but I am not sure.

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1. Note that if you have sin(kx-b) that gives you little information about the phase shift. You will need to plot a bunch of points to see the graph.

But, if you write that as sin( k(x-b/k) ) you can see immediately that the shift is (b/k) to the right. You can still see that the period is 2π/k, but now you can also see the shift.

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2. excellent response.

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