Trigonometry

True or False
The left side of cos^4 θ + (cos^2 θ)(sin^2 θ) + sin^2 θ = 1 can be factored to cos^2 θ(cos^2 θ + sin^2 θ) + sin^2 θ.

  1. 👍 0
  2. 👎 0
  3. 👁 219
  1. I would strongly suggest that you expand
    cos^2 θ(cos^2 θ + sin^2 θ) + sin^2 θ
    and see what you get.

    1. 👍 0
    2. 👎 0
  2. I got 1. Thank you!

    1. 👍 0
    2. 👎 0
  3. The factoring is correct, but it's not 1.

    1. 👍 0
    2. 👎 0
  4. Every time I expand it I get 1.

    1. 👍 0
    2. 👎 0
  5. you are missing a factor of 2.
    (cos^2 θ + sin^2 θ)^2 = cos^4 θ + 2(cos^2 θ)(sin^2 θ) + sin^4 θ = 1

    1. 👍 0
    2. 👎 0
  6. So it's false?

    1. 👍 0
    2. 👎 0
  7. NO!
    The left side factors as indicated.
    The problem is, that it does not equal 1.

    Maybe you typed the question wrong.

    1. 👍 0
    2. 👎 0
  8. Oh, well I copied it directly from the assignment. Maybe there was a mistake made there.

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math Help Please

    What are the ratios for sin A and cos A? The diagram is not drawn to scale. Triangle Description- AB = 29 AC = 20 BC - 21 A. sin A = 20/29, cos A = 21/29 B. sin A = 21/29, cos A = 20/21 C. sin A = 21/29, cos A = 20/29****? D. sin

    asked by Battia Anne on June 7, 2016
  2. Trig.......

    I need to prove that the following is true. Thanks (2tanx /1-tan^x)+(1/2cos^2x-1)= (cosx+sinx)/(cosx - sinx) and thanks ........... check your typing. I tried 30º, the two sides are not equal, they differ by 1 oh , thank you Mr

    asked by abdo on April 18, 2007
  3. calculus

    Find complete length of curve r=a sin^3(theta/3). I have gone thus- (theta written as t) r^2= a^2 sin^6 t/3 and (dr/dt)^2=a^2 sin^4(t/3)cos^2(t/3) s=Int Sqrt[a^2 sin^6 t/3+a^2 sin^4(t/3)cos^2(t/3)]dt =a Int

    asked by ms on September 18, 2013
  4. TRIG!

    Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x +

    asked by hayden on February 23, 2009
  5. solving trig. equations

    tan(3x) + 1 = sec(3x) Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes secx and... secx = secx sec(3x) = sec(3x) [just put 3x back in for x- you don't really have to change 3x

    asked by Jen on April 12, 2007
  1. Mathematics - Trigonometric Identities

    Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) =

    asked by Anonymous on November 8, 2007
  2. Trig

    Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v - u) tan (v + u) First compute or list the cosine and sine of both u and v. Then use the combination rules sin (v + u) = sin u cos v + cos v

    asked by Nan on December 29, 2006
  3. maths

    Choose three options which are true: a) an angle of 150 degrees is equivalent to 2pie/3 radians. b) Cos 0 = cos (0 – pie/2) for al values of 0. c) Sin 0 = cos (0 – pie/2) for all values of 0. d) If triangle ABC has a right

    asked by kat on June 8, 2007
  4. Calculus 12th grade (double check my work please)

    1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.-2 sin 2x B.-2 sin 2x / sinh 3y C.-2/3tan (2x/3y) D.-2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) with

    asked by anon on March 6, 2011
  5. Trig

    Find sin(s+t) and (s-t) if cos(s)= 1/5 and sin(t) = 3/5 and s and t are in quadrant 1. =Sin(s)cos(t) + Cos(s)Sin(t) =Sin(1/5)Cos(3/5) + Cos(-1/5)Sin(3/5) = 0.389418 Sin(s-t) =sin(s)cos(t) - cos(s)sin(t) =sin(-3/5)cos(1/5) -

    asked by Sally on May 7, 2015
  6. Math

    State the restrictions on the variables for these trigonometric identities. a)(1 + 2 sin x cos x)/ (sin x + cos x) = sin x + cos x b) sin x /(1+ cos x) = csc x - cot x

    asked by Emily on December 22, 2010

You can view more similar questions or ask a new question.