divide 75 units into parts,such that the product is 1250
one part --- x
the other part ---- 75-x
x(75-x) = 1250
-x^2 + 75x - 1250 = 0
x^2 - 75x + 1250 = 0
(x-50)(x-25) = 0
etc
Eq1: x + y = 75.
Eq2: xy = 1250,
y = 1250/x,
In Eq1, replace y with 1250/x and solve for x:
x + 1250/x = 75,
x^2 + 1250 = 75x,
x^2 - 75x + 1250 = 0,
(x-50)(x-25) = 0.
To divide 75 units into parts such that the product is 1250, we need to find two numbers whose product is 1250 and whose sum is 75.
Here's how you can find those numbers:
Step 1: Start by finding the factors of 1250.
The factors of 1250 are:
1, 2, 5, 10, 25, 50, 125, 250, 625, and 1250.
Step 2: Look for two numbers whose product is 1250 and whose sum is 75.
Starting from the largest factors, we can try to find such numbers. We can start by testing 50 and 25.
50 * 25 = 1250
50 + 25 = 75
So, we have found the two numbers: 50 and 25.
Step 3: Divide the original amount (75 units) into those two parts.
Since the sum of the two numbers is 75, we know that 50 units and 25 units will give us the desired result.
Therefore, to divide 75 units into parts such that the product is 1250, you would have 50 units and 25 units.