Two masses are moving down a slope. One mass is traveling twice as fast as the other mass. How does the kinetic energy of one mass compare to the other?
i don't understand
Your school work is more important, at this point in your life, than your social life.
KE. = 1/2*m*v^2
1it depends on the masses and/or where the masses first started to Move down the slope. More information is needed to dome to a conclusion.
uh.... I have to get back to you on this bc I have other work that is overdue um... can you just scroll down to my other science post and check my answers? please my parents will kill me if I don't have all A's, I need you, my social life depends on you.
i guess, but plz explain your answer there i need help
I need the answers
To understand how the kinetic energy of one mass compares to the other, we need to know the relationship between kinetic energy and velocity. The formula for kinetic energy is:
Kinetic Energy = (1/2) * mass * velocity^2
According to the question, one mass is traveling twice as fast as the other. Let's denote the velocity of the slower mass as "v" and the velocity of the faster mass as "2v".
To compare their kinetic energies, let's calculate them individually:
For the slower mass:
Kinetic Energy (1) = (1/2) * mass * v^2
For the faster mass:
Kinetic Energy (2) = (1/2) * mass * (2v)^2 = (1/2) * mass * 4v^2 = 2 * (1/2) * mass * v^2 = 2 * Kinetic Energy (1)
So we can see that the kinetic energy of the faster mass is twice that of the slower mass.
1it=it
Dome=come