Given the following thermochemical equation:
2 SO2 + O2 => 2 SO3 + 4300 kJ
What is the heat change in kJ accompanying the production of 43.0 grams of SO3?
So 4300 kJ heat us released upon the formation of 2*80 or 160 g SO3. Use a proportion or this.
4300 kJ x (43.0/160) = ?
The proportion would look like this
(4300/160) = (x/43.0) and solve for x.
thank you
To find the heat change in kJ accompanying the production of 43.0 grams of SO3, you need to use the stoichiometry of the thermochemical equation and the molar mass of SO3.
1. Calculate the molar mass of SO3:
- The molar mass of sulfur (S) is 32.07 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol.
- SO3 consists of 1 sulfur atom and 3 oxygen atoms.
- Therefore, the molar mass of SO3 is:
Molar mass = (1 * S molar mass) + (3 * O molar mass)
= (1 * 32.07 g/mol) + (3 * 16.00 g/mol)
= 80.07 g/mol
2. Calculate the number of moles of SO3:
- Number of moles = Mass / Molar mass
- Mass of SO3 = 43.0 grams
- Number of moles = 43.0 g / 80.07 g/mol
3. Use the stoichiometry of the thermochemical equation to find the heat change in kJ:
- According to the balanced equation, the heat change is 4300 kJ when 2 moles of SO2 react to produce 2 moles of SO3.
- So, the heat change for 1 mole of SO3 is 4300 kJ / 2 moles = 2150 kJ.
- Multiply the heat change for 1 mole of SO3 by the number of moles calculated in step 2 to get the heat change for 43.0 grams of SO3.
Therefore, the heat change in kJ accompanying the production of 43.0 grams of SO3 can be calculated using the above steps.