H2SO4 solution containing 200.1g of H2S04 in 0.3500l of solution at 20 degree celcius has a density of 1.3294g/ml. find a,mass percent of H2SO4 b,molarity c,molality
mass percent= 200.1/(200.1+.350*1.3294)= ?
Molarity= moles/volume=(200.1/98)/.350
Molality= (200.1/98)/(.35*1.3294)
You may want to calculate molecuar mass to 4 decimal places, and not use 98.
Be careful:
Molality=mole of solute/kg of solvent
Molality= (200.1/98)/(.35*1.3294)
They solution above will return moles of solute/ g of solvent
Molality= (200.1/98)/[(.35*1.3294)*(1kg/1,000g)]=moles of solute/kg of solvent
Nevermind. He didn't change L to mL which would return the same answer as if he did so of the proper conversions. He skipped a step and did not explain why.
To find the mass percent of H2SO4, we need to calculate the mass of H2SO4 in the solution and then divide it by the total mass of the solution. The formula for mass percent is:
Mass Percent = (Mass of component / Mass of solution) x 100
a) Mass of H2SO4:
Given: Mass of solution = 200.1g
Density = 1.3294g/ml
Volume of solution = 0.3500L = 350 ml
To find the mass of H2SO4, we can use the density equation:
Density = Mass / Volume
Rearranging the equation to solve for the mass:
Mass = Density x Volume
Mass = 1.3294 g/ml x 350 ml
Mass = 465.29 g
Now we can calculate the mass percent:
Mass Percent = (465.29g / 200.1g) x 100
Mass Percent = 232.52%
Therefore, the mass percent of H2SO4 in the solution is 232.52%.
b) To find the molarity of the H2SO4 solution, we need to use the formula:
Molarity = (moles of solute / volume of solution in liters)
First, we need to calculate the number of moles of H2SO4:
Moles of H2SO4 = mass of H2SO4 / molar mass of H2SO4
The molar mass of H2SO4 is:
2(1.01g/mol for H) + 32.07g/mol for S + 4(16.00g/mol for O)
= 98.09 g/mol
Moles of H2SO4 = 200.1g / 98.09g/mol
Moles of H2SO4 = 2.042 mol
Now, we can calculate the molarity:
Molarity = 2.042 mol / 0.3500 L
Molarity = 5.84 M
Therefore, the molarity of the H2SO4 solution is 5.84 M.
c) To find the molality of the H2SO4 solution, we need to use the formula:
Molality = (moles of solute / mass of solvent in kg)
We have already calculated the moles of H2SO4 as 2.042 mol. Now, we need to convert the volume of the solution to mass of solvent:
Mass of solvent = Density of solvent x Volume of solvent
Since the density of the solution is given as 1.3294 g/mL, we can assume the density of the solvent (water) is also approximately 1 g/mL.
Mass of solvent = 1 g/mL x 350 mL
Mass of solvent = 350 g
Now, we can calculate the molality:
Molality = 2.042 mol / 0.350 kg
Molality = 5.84 mol/kg
Therefore, the molality of the H2SO4 solution is 5.84 mol/kg.