Re-write 2x - 3y >_ 6 in slope- intercept format.
its an equal or greater than sign by the way. Can someone help me? I can't figure out how.
2x - 3y ≥ 6
-3y ≥ -2x + 6
divide by -3, which means we have to reverse the inequality sign
y ≤ (2/3)x - 2
which represents the region below the line y = (2/3)x - 2, including all points
on the line itself.
recall that the slope-intercept format is y = mx+b
So, you need to get y all alone on the left.
2x - 3y >= 6
3y <= 2x + 6
y <= 2/3 x + 2
generally, slope-intercept form is used for lines (equations), not inequalities ...
oops. that pesky - sign
I get it now. Gracias Chicos!!
To rewrite the inequality 2x - 3y ≥ 6 in slope-intercept form, we need to isolate y on one side of the equation.
First, let's move the 2x term to the other side of the inequality by subtracting 2x from both sides:
-3y ≥ -2x + 6
Next, divide both sides of the inequality by -3 (since we want to isolate y):
y ≤ (-2x + 6) / -3
Finally, simplify the right side of the equation:
y ≤ (2/3)x - 2
So, the inequality 2x - 3y ≥ 6 in slope-intercept form is y ≤ (2/3)x - 2.