Math

ѕolve
хy=80
logх-2logy=1

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  1. taking logs of first equation:
    logx + logy=log80
    now subtracting that from the second initial equation
    -3logy=1-log80
    note that 1=log10
    1/y^3=10/80
    y= cubrt(8)=2
    check my work

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