Write an equation in Slope-Intercept form of the line that passes through given point and is parallel to the graph of the given equation.
(2,-2) ; y=-x-2
a) y=-2x
B) y=2x
c) y=1/2x
d) y=-x
Can Somone Pls help its urgent!!!!
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i need help ASAP Please
It must be urgent because the question is on a test. Tests are designed to find out what a student knows, not what somebody online claims to know.
To find the equation of a line that is parallel to the given equation and passes through the given point, we can use the fact that parallel lines have the same slope.
The given equation is y = -x - 2, which is in the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
The slope of the given equation is -1 since the coefficient of x is -1. Therefore, any line parallel to this equation will also have a slope of -1.
Now that we have the slope, -1, and the given point, (2, -2), we can use the point-slope form of a linear equation to find the equation of the line.
The point-slope form of a linear equation is y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope.
Substituting the values into the point-slope form, we have:
y - (-2) = -1(x - 2)
y + 2 = -x + 2
Simplifying, we get:
y = -x + 2 - 2
y = -x
Therefore, the equation of the line that is parallel to the given equation and passes through the point (2, -2) is y = -x.
So, the correct answer is d) y = -x.