Given ABC with a = 8, b = 14, and mA 28°, find the number of distinct solutions

I got 2 solutions

I agree.

And what would those 2 solutions be ?
Show me the steps you took to get at least one of them.

To find the number of distinct solutions in a triangle using the given side lengths and angle measurements, we can use the law of sines.

The law of sines states that in a triangle, the ratio of the length of a side to the sine of its opposite angle is constant. Mathematically, it can be expressed as:

a/sin(A) = b/sin(B) = c/sin(C)

In this case, we are given side lengths a = 8, b = 14, and angle A = 28°. We can find angle B by using the law of sines:

b/sin(B) = a/sin(A)

Plugging in the given values:

14/sin(B) = 8/sin(28°)

Now, solve for sin(B):

sin(B) = (14 * sin(28°)) / 8

Using a calculator, evaluate sin(B) ≈ 0.532

Now, find angle B by taking the inverse sine (sin^(-1)) of 0.532:

B ≈ sin^(-1)(0.532) ≈ 32.2°

Since angle C is the sum of angles A and B in a triangle (180°), we can find angle C:

C = 180° - A - B
= 180° - 28° - 32.2°
≈ 119.8°

So, we have found the measures of all three angles in the triangle: A = 28°, B ≈ 32.2°, and C ≈ 119.8°.

Now, let's determine the number of distinct solutions.

In general, a triangle can have:
- One unique solution if the given side lengths and angle measurements allow a triangle to be formed.
- Two distinct solutions if a triangle can be formed with the given side lengths but with different angle measurements.
- No solution if it is not possible to form a triangle with the given side lengths.

Based on the given side lengths and angle measurements, it is possible to form a triangle. Therefore, we can conclude that there are two distinct solutions for the triangle ABC.