A battery is made of 3cells in series. Each cell hasε= 2.20V, r = 0.0100Ω. The battery is connected to a 3.27Ωload. Calculate the potential difference across the load.

I = E/(r+Rl) = 3*2.2/(0.01+3.27) = 2.012A.

V = I * Rl = 2.012 * 3.27 =

Same type of problem, different names? Huummm

total ε is ... 3 * 2.20 v

total r is ... 3.27Ω + (3 * 0.0100Ω)

find circuit current

calculate load potential

Correction:

I = 6.6/(0.03+3.27) = 2A.
V = I * Rl = 2 * 3.27 =

To calculate the potential difference across the load, we need to first calculate the total electromotive force (EMF) of the battery, and then take into account the internal resistance of the battery.

1. Calculate the total EMF of the battery:
The battery consists of 3 cells in series, and each cell has an EMF of ε = 2.20V. Since the cells are connected in series, the total EMF of the battery can be calculated by multiplying the individual EMFs:
Total EMF = ε × Number of cells = 2.20V × 3 = 6.60V

2. Calculate the total internal resistance of the battery:
Each cell has an internal resistance of r = 0.0100Ω. Since the cells are connected in series, the total internal resistance of the battery can be calculated by summing up the resistances:
Total internal resistance = r × Number of cells = 0.0100Ω × 3 = 0.0300Ω

3. Calculate the potential difference across the load:
The potential difference across the load can be calculated using Ohm's Law:
Potential difference across the load = Total EMF - (Total internal resistance × Current)
Since the current flowing through the load is the same as the current flowing through the internal resistance (due to series connection), we can calculate the current using Ohm's Law:
Current = Total EMF / (Total internal resistance + Load resistance)

Substituting the given values:
Current = 6.60V / (0.0300Ω + 3.27Ω) = 6.60V / 3.30Ω = 2.00A (rounded to two decimal places)

Now, substitute the calculated current into the potential difference formula:
Potential difference across the load = 6.60V - (0.0300Ω × 2.00A) = 6.60V - 0.06V = 6.54V

Therefore, the potential difference across the load is approximately 6.54V.