Physics

Two light bulbs are connected in series. The resistance of the filament of the first light bulb is 230Ω. The potential difference across the first light bulb is 100V and across the second light bulb,200V. What is the resistance of the second light bulb?

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asked by exo-L
  1. twice the voltage drop means twice the resistance

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    posted by R_scott
  2. I = V1/R1 = 100/230 = 0.435A.
    R2 = V2/I = 200/0.435 =

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    posted by Henry2

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