A battery (ε= 10.0V, r = 0.50Ω) is connected to three light bulbs in series (R1= 15.0Ω, R2= 21.0Ω, R3= 24.0Ω). Calculate the current delivered by the battery.
I = E/(r+R1+R2+R3) = 10/(0.5+15+21+24) = 0.165A.
To calculate the current delivered by the battery, we can use Ohm's law and the concept of series circuits.
In a series circuit, the current flowing through each component is the same. So, we need to determine the total resistance of the circuit first.
To find the total resistance (R_total) of a series circuit, we sum up the resistances of all the components:
R_total = R1 + R2 + R3
Let's calculate the total resistance:
R_total = 15.0Ω + 21.0Ω + 24.0Ω
= 60.0Ω
Now we can use Ohm's law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):
I = V / R
In this case, the voltage of the battery (V) is 10.0V, and the total resistance (R_total) is 60.0Ω.
I = 10.0V / 60.0Ω
= 0.1667 A (rounded to four decimal places)
Therefore, the current delivered by the battery is approximately 0.1667 Amperes.