A battery (ε= 10.0V, r = 0.50Ω) is connected to three light bulbs in series (R1= 15.0Ω, R2= 21.0Ω, R3= 24.0Ω). Calculate the current delivered by the battery.

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  1. I = E/(r+R1+R2+R3) = 10/(0.5+15+21+24) = 0.165A.

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