A 500 g piece of iron changes 7°C when heat is added. How much heat energy produced this change in temperature? C of iron is 0.450 J/g°C

q (inJoules) = mass Fe x specific heat Fe x delta T

Substitute and solve for q.

Well, that's quite a hot topic! Let's do some math to calculate the heat energy produced.

Given:
Mass of iron = 500 g
Change in temperature = 7°C
Specific heat capacity of iron = 0.450 J/g°C

To calculate the heat energy produced, we can use the formula:
Q = m * c * ΔT

Where:
Q is the heat energy produced,
m is the mass of the iron,
c is the specific heat capacity of iron,
and ΔT is the change in temperature.

So, plugging in the values:
Q = 500 g * 0.450 J/g°C * 7°C

Multiplying these values together gives us the heat energy produced, which is... *drumroll please* ...

1575 J! That's the amount of heat energy produced in this change in temperature. Don't worry, the iron didn't melt or become a hot potato in the process!

To calculate the heat energy produced when the temperature of the iron changes, you can use the formula:

Q = m * C * ΔT

Where:
Q is the heat energy (in Joules),
m is the mass of the iron (in grams),
C is the specific heat capacity of the iron (in J/g°C), and
ΔT is the change in temperature (in °C).

Given:
m = 500 g
C = 0.450 J/g°C
ΔT = 7°C

Substituting these values into the formula, we get:

Q = 500 g * 0.450 J/g°C * 7°C

Q = 1575 J

Therefore, the heat energy produced when the temperature of the iron changes by 7°C is 1575 Joules.

To find the amount of heat energy produced, you can use the formula:

Q = m * C * ΔT

Where:
Q is the heat energy produced
m is the mass of the iron (500 g)
C is the specific heat capacity of iron (0.450 J/g°C)
ΔT is the change in temperature (7°C)

Now, we can plug in the values:

Q = 500 g * 0.450 J/g°C * 7°C

First, multiply the mass and the specific heat capacity:

Q = 225 J/°C * 7°C

Next, multiply the result by the change in temperature:

Q = 1575 J

Therefore, the amount of heat energy produced for this change in temperature is 1575 Joules.