# math

In ΔABC, m∠ACB = 90°,
CD⊥ AB and m∠ACD = 45°
Find :AC, if CD = 6 sqrt2 in.

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1. If you make your sketch, it is easy to see that ∠CAD is also 45°
giving you an isosceles right-angled triangle, thus
AC^2 = (6√2)^2 + (6√2)^2
= 72+72 = 144
AC = 12

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