Michael has $1,000.71 in his checking account. He is going to spend $482.41 on a new television, and he will spend the rest on speakers that cost $46.00 each. Which of the following inequalities would determine the maximum number of speakers, x, Michael can buy without spending more money than he has in his account?
A.
$46.00x + $482.41 < $1,000.71
B.
$1,000.71 < $46.00x + $1,000.71
C.
$482.41 + $46.00 + x < $1,000.71
D.
$1,000.71 + $482.41 > $46.00 + x
merciiii
well, x speakers cost $46x, right?
and the sum of it all has to be less than $1000.71, right?
so, ...
$46.00 each means you have to multiply by the number of speakers to get the total cost
the cost of the tv plus the speakers has to be less than his account balance
To determine the maximum number of speakers, x, that Michael can buy without spending more money than he has in his account, we need to consider the total amount Michael will spend on the television and speakers and compare it to the amount he has in his checking account.
First, we know that Michael will spend $482.41 on a new television. Next, we need to find out how much he will spend on speakers. Each speaker costs $46.00, and the total amount Michael has will determine how many speakers he can buy.
So, we can write an inequality to represent the situation:
$46.00x + $482.41 ≤ $1,000.71
In this inequality, $46.00x represents the total amount Michael will spend on speakers (46 dollars per speaker, multiplied by the unknown number of speakers, x). $482.41 represents the amount Michael will spend on the television, and $1,000.71 represents the total amount he has in his checking account.
The inequality expresses that the total amount spent on the television and speakers cannot exceed the amount Michael has in his account.
Therefore, the correct inequality for this scenario is:
A. $46.00x + $482.41 < $1,000.71