Find 5 consecutive whole numbers if it is known that the sum of the squares of the first 3 numbers is equal to the sum of the squares of the last 2 numbers.

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asked by Sam
  1. let the numbers be x-2, x-1, x, x+1, x+2
    Then you know that
    (x-2)^2 + (x-1)^2 + x^2 = (x+1)^2 + (x+2)^2
    Now find x, and you have the middle number.

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    posted by Steve

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