2. Ammonia is produced by the reaction of hydrogen and nitrogen. N2(g) + 3H2(g) à 2NH3(g)

o a. How many moles of H2 are needed to react with 1.0 mol of N2?
o b. How many moles of N2 reacted if 0.60 mol of NH3 is produced?
o c. How many moles of NH3 are produced when 1.4 mol of H2 reacts?

N2(g) + 3H2(g) -----> 2NH3(g)

All your answers are right there since the equation is balanced.
for every 6*10^23 molecules of N2 you need 3 * 6*10^23 molecules of H2
In other words 3 mols of H2 for every mol of N2

Nitrogen and hydrogren react to produce ammonia.

N2(g) + 3H2(g) --> 2NH3(g)

How many moles of hydrogren are needed to produce 10.0 mol of ammonia?

To answer these questions, we will use the stoichiometry of the balanced chemical equation.

a. How many moles of H2 are needed to react with 1.0 mol of N2?

From the balanced equation: N2(g) + 3H2(g) -> 2NH3(g)

Comparing the coefficients, we can see that 1 mole of N2 reacts with 3 moles of H2.

Therefore, to react with 1.0 mol of N2, you would need 1.0 mol of N2 x 3 mol of H2 / 1 mole of N2 = 3.0 moles of H2.

b. How many moles of N2 reacted if 0.60 mol of NH3 is produced?

Again, using the balanced equation: N2(g) + 3H2(g) -> 2NH3(g)

Comparing the coefficients, we can see that for every 2 moles of NH3 produced, 1 mole of N2 reacts.

Therefore, to calculate the moles of N2 reacted, we will use the ratio between NH3 and N2 in the balanced equation.

0.60 mol of NH3 x 1 mol of N2 / 2 mol of NH3 = 0.30 moles of N2.

c. How many moles of NH3 are produced when 1.4 mol of H2 reacts?

Once again, using the balanced equation: N2(g) + 3H2(g) -> 2NH3(g)

Comparing the coefficients, we can see that for every 3 moles of H2, 2 moles of NH3 are produced.

Therefore, to calculate the moles of NH3 produced, we will use the ratio between H2 and NH3 in the balanced equation.

1.4 mol of H2 x 2 mol of NH3 / 3 mol of H2 = 0.933 moles of NH3.

To determine the number of moles of H2 needed to react with 1.0 mol of N2, you can use the balanced chemical equation. According to the equation, 3 moles of H2 react with 1 mole of N2. Therefore, you would need 3.0 moles of H2 to react with 1.0 mole of N2.

To determine the number of moles of N2 that reacted if 0.60 mol of NH3 is produced, you can also use the balanced chemical equation. According to the equation, 1 mole of N2 reacts to form 2 moles of NH3. Therefore, for every 2 moles of NH3 produced, 1 mole of N2 reacts. In this case, 0.60 mol of NH3 was produced, so you would need to divide it by 2 to find the number of moles of N2 reacted. Thus, 0.60 mol of NH3 would correspond to 0.30 mol of N2 reacted.

Similarly, to determine the number of moles of NH3 produced when 1.4 mol of H2 reacts, you can use the balanced chemical equation. According to the equation, 3 moles of H2 react to form 2 moles of NH3. Therefore, for every 3 moles of H2, you would produce 2 moles of NH3. In this case, 1.4 mol of H2 reacts, so you would need to calculate the corresponding moles of NH3. To do this, you can set up a ratio:

(1.4 mol H2 / 3 mol H2) x (2 mol NH3 / 1 mol H2) = 0.93 mol NH3

Therefore, 1.4 mol of H2 reacting would produce 0.93 mol of NH3.