How does finding the square root [J ] of a number compare to fnding the cube root [3 J- ] of
a number? Use the number 64 in your explanation.
64 = 4^3 = 8^2
In general, there's noting to compare, but it helps if the number is a 6th power, like 64, since
(x^2)^3 = (x^3)^2 = x^6