Calculate s50 for the arithmetic sequence defined by (an)=(71-2.3n)
To find the value of s50, we need to understand that s50 represents the sum of the first 50 terms of the arithmetic sequence, where (an) = 71 - 2.3n.
To calculate s50, we will use the formula for the sum of n terms of an arithmetic sequence:
s_n = (n/2) * (a_1 + a_n)
Where:
s_n = sum of n terms
a_1 = first term of the sequence
a_n = nth term of the sequence
n = number of terms
In this case, we need to calculate s50. Therefore, n = 50, a_1 = a_1 = (71 - 2.3*1) = 68.7 (substituting n = 1 into the given sequence).
To find a_50, we substitute n = 50 into the given sequence:
a_50 = 71 - 2.3*50
= 71 - 115
= -44
Now we can substitute the values into the formula to find s50:
s50 = (50/2) * (68.7 + (-44))
= 25 * (24.7)
= 617.5
Therefore, s50 for the given arithmetic sequence is 617.5.
do it the same way I just showed you
I’m having trouble would I do a(50)=71-(2.3n)(50)
a(50)=71-(2.3n)(50)
doesn't even remotely resemble the formula I gave you.
What was your a ? What was your d ??