i dont understand how you get the 2xln(2) mine is ln(4)
dy/dx = ( 4^x (1) - x(4^x)(ln4) )/ 4^(2x) = 4^x( 1 - xln4)/4^(2x) = ( 1 - xln4)/4^x can you see it ? The tricky part is ln 4 = ln (2^2) = 2ln2 I really don't see the point of doing that "simpification"
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