an isosceles triangle has a perimeter of (9y-15)cm.what is the length of each of the two equal sides,if its third sides is (3y-7)cm
let each of the equal sides be s
2s + 3y-7 = 9y-15
2s = 6y -8
s = 3y - 4
Yeah
To find the length of each of the two equal sides of the isosceles triangle, we first need to express the perimeter in terms of a single variable, y.
Given that the perimeter is (9y-15) cm, we can set up an equation as follows:
Perimeter = sum of all sides
(9y-15) = 2(equal sides) + (3y-7)
Now, let's solve for the length of each equal side.
First, combine like terms on the right side of the equation:
9y - 15 = 2equal sides + 3y - 7
Next, simplify the equation by combining like terms with the variable y:
9y - 15 - 3y = 2equal sides - 7
Simplifying further:
6y - 15 = 2equal sides - 7
Now, let's isolate the variable on one side of the equation by moving the constant term (-7) to the other side:
6y - 15 + 7 = 2equal sides
Combine the constant terms:
6y - 8 = 2equal sides
Now, divide both sides of the equation by 2 to solve for the length of each equal side:
(6y - 8)/2 = equal side length
Simplifying further:
3y - 4 = equal side length
Therefore, the length of each of the two equal sides of the isosceles triangle is (3y-4) cm.