Calculus

Given the function f(x)=[h(p(x))]^2 and h(5)=1, h'(5)=2, h'(1)=3, p(1)=5, p'(1)=7, evaluate f'(1).

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  1. f=(h(p))^2
    f' = 2h*h'*p'
    f'(1) = 2h(p(1))*h'(p(1))*p'(1) = 2h(5)*h'(5)*p(1) = 2*1*2*7 = 28

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