What is the distance between the points (-3, 2) and (-7, 7) on the coordinate plane?
(-3, 2), (-7, 7).
d^2 = (-7+3)^2 + (7-2)^2 =
i got 25.
the possible answers were √9
√41
√56
√68
To find the distance between two points on a coordinate plane, we can use the distance formula. The distance formula is:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Let's plug in the values:
x1 = -3
y1 = 2
x2 = -7
y2 = 7
Substituting these values into the distance formula, we get:
d = √((-7 - (-3))^2 + (7 - 2)^2)
Simplifying the equation:
d = √((-7 + 3)^2 + (7 - 2)^2)
= √((-4)^2 + (5)^2)
= √(16 + 25)
= √41
So, the distance between the points (-3, 2) and (-7, 7) is √41 (approximately 6.403).
To find the distance between two points in a coordinate plane, we can use the distance formula.
The distance formula is:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Let's use this formula to find the distance between the points (-3, 2) and (-7, 7):
x1 = -3, y1 = 2
x2 = -7, y2 = 7
Plugging these values into the distance formula, we have:
d = √((-7 - (-3))^2 + (7 - 2)^2)
= √((-7 + 3)^2 + (7 - 2)^2)
= √((-4)^2 + (5)^2)
= √(16 + 25)
= √41
Therefore, the distance between the points (-3, 2) and (-7, 7) is √41 units.