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The perimeter of a rectangle is 66m. if the width were doubled and the length were increased by 24m, the perimeter would be 132m. What are the length and width of the rectangle

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  1. original:
    length --- x
    width ---- y
    2x + 2y = 66
    x+y = 33
    y = 33-x

    new rectangle:
    length ---- x+24
    width = 2y
    perimeter= 2(x+24) + 2(2y) = 132
    2x + 48 + 4y = 132
    2x + 48 + 4(33-x) = 132
    -2x + 180 = 132

    take over

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