A 85 kg man weighs 833 N on the Earth's surface. How far above the surface of the Earth would he have to go to "lose" 18% of his body weight?

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  1. gravitational force (weight) is inversely proportional to the square of the distance between the masses

    Earth radius ... 6.38E6 m

    [6.38E6 / (6.38E6 + h)^2 = 1 - .18 ... 6.38E6 = (h + 6.38E6) √.82

    solve for h

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