6g of metal M react completely with 23.66g of chlorine to form 29.66 of the metallic chloride. Find the empirical formula of the metallic chloride ( M=27,CL= 35.5)
find the ratio of the moles ... (6 / 27) + (23.66 / 35.5) --> ?
To find the empirical formula of the metallic chloride, we first need to determine the number of moles of metal M and chlorine.
1. Calculate the number of moles of metal M:
Moles of metal M = Mass of metal M / molar mass of metal M
Moles of metal M = 6g / 27 g/mol (given that M = 27)
Moles of metal M = 0.222 mol
2. Calculate the number of moles of chlorine:
Moles of chlorine = Mass of chlorine / molar mass of chlorine
Moles of chlorine = 23.66g / 35.5 g/mol (given that Cl = 35.5)
Moles of chlorine = 0.667 mol
3. Find the mole ratio between metal M and chlorine:
Divide the number of moles of each element by the smallest number of moles to get the mole ratio.
Mole ratio = Moles of metal M / Moles of chlorine
Mole ratio = 0.222 mol / 0.222 mol (since 0.222 mol is the smallest value)
Mole ratio = 1:3
The mole ratio indicates that the empirical formula of the metallic chloride is MCl3.