Suzanne is 4 years elder to her brother Robert. If sumit of their ages is 22 years, find how old is Suzanne and Robert are?
s = r+4
s+r = 22
now just solve for s and r
Robert is X yrs. old.
Suzanne is x+4 yrs. old.
x + (x+4) - 22.
Let's solve this step-by-step:
Step 1: Let's assume Robert's age as 'x'.
Step 2: As Suzanne is 4 years older than Robert, her age would be (x + 4).
Step 3: The sum of their ages is given as 22 years. So we can write the equation:
x + (x + 4) = 22
Step 4: Simplify the equation:
2x + 4 = 22
Step 5: Subtract 4 from both sides:
2x = 18
Step 6: Divide both sides by 2:
x = 9
Step 7: Thus, Robert is 9 years old.
Step 8: Suzanne's age can be calculated by substituting the value of x in the equation:
Suzanne's age = x + 4 = 9 + 4 = 13
Step 9: Therefore, Suzanne is 13 years old.
To summarize, Robert is 9 years old, and Suzanne is 13 years old.
To find the ages of Suzanne and Robert, we can use a system of equations. Let's assign variables to their ages.
Let's say Suzanne's age is "S" and Robert's age is "R".
We have two pieces of information from the question:
1) Suzanne is 4 years older than Robert, so we can write an equation:
S = R + 4
2) The sum of their ages is 22, so we can write another equation:
S + R = 22
Now we can solve these equations simultaneously to find the values of S and R.
Substitute the value of S from the first equation into the second equation:
R + 4 + R = 22
Combine like terms:
2R + 4 = 22
Subtract 4 from both sides:
2R = 18
Now divide both sides by 2:
R = 9
Now substitute the value of R back into the first equation to find S:
S = R + 4
S = 9 + 4
S = 13
So, Suzanne is 13 years old, and Robert is 9 years old.