physics

Two children with masses of 24 and 31 kg are sitting on a balanced seesaw. If the lighter child is sitting 3 m from the center, where is the heavier child sitting?

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  1. Tcw=Tccw

    Fsind=Fsind

    (24kg)(3m)=(31kg)(x-3)

    Gravity (g) on both sides of equation and cancel.

    Solve for x:

    72=31x-39

    111=31x

    X=3.6m

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  2. the heavier child has to be closer to the center , not farther away

    (24 kg) * (3 m) = (31 kg) * (x m)

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  3. That is correct.

    Tcw=Tccw

    Fsind=Fsind

    (24kg)(3m)=(31kg)(x)

    Gravity (g) on both sides of equation and cancel.

    Solve for x:

    72=31x
    72/31=x

    X=2.3m

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