# physics

Two children with masses of 24 and 31 kg are sitting on a balanced seesaw. If the lighter child is sitting 3 m from the center, where is the heavier child sitting?

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1. Tcw=Tccw

Fsind=Fsind

(24kg)(3m)=(31kg)(x-3)

Gravity (g) on both sides of equation and cancel.

Solve for x:

72=31x-39

111=31x

X=3.6m

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2. the heavier child has to be closer to the center , not farther away

(24 kg) * (3 m) = (31 kg) * (x m)

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2. 👎 1
3. That is correct.

Tcw=Tccw

Fsind=Fsind

(24kg)(3m)=(31kg)(x)

Gravity (g) on both sides of equation and cancel.

Solve for x:

72=31x
72/31=x

X=2.3m

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2. 👎 0

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