Physics

A rock is dropped into an abandoned mine and a splash is heard 2 s later. Assuming that it takes a negligible time for the sound to travel up the mine shaft, determine the depth of the shaft and how fast the rock was falling when it hit the water.

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  1. In other words how far did it fall in 2 seconds
    I assume you are using the metric system and g = 9.81 m/s^2
    h = (1/2) g t ^2 = 4.9 t^2 = 4.9 * 4

    v = g t = 9.81 * 2 meters/second

    in general:
    if a = -9.81
    v = Vi - 9.81 t
    y = Yi + Vi t - 4.9 t^2
    here y is 0, ground
    Vi is 0, initial velocity
    Yi is height, what we want to know

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