The primary coil of a transformer has 739 loops. The secondary coil has 953,677 loops. The primary coil has a 76 A current and 58 V.
b.) Determine the power of the primary coil.
W
c.) Assuming no losses, determine the power of the secondary coil.
W
d.) Calculate the voltage in the secondary coil.
V
e.) Calculate the current in the secondary coil.
A
b. Wondering what the Power factor is. Assuming PF of 1, that is current and voltage is in phase.... Power = 76*58 watts
c. has to be the same.
d. Vs=Vp*Ns/Np
e. Is=Ip*Np/Ns low current.
To answer these questions, we can use the formulas related to transformer operation.
a.) We are given the number of loops in the primary coil (Np = 739), the number of loops in the secondary coil (Ns = 953,677), the primary current (Ip = 76 A), and the primary voltage (Vp = 58 V). To find the power of the primary coil, we can use the formula:
Power = Voltage * Current
Plugging in the given values, we get:
Power_primary = Vp * Ip = 58 V * 76 A = 4408 W
Therefore, the power of the primary coil is 4408 W.
b.) Assuming no losses, the power of the secondary coil is equal to the power of the primary coil. So, the power of the secondary coil is also 4408 W.
c.) To calculate the voltage in the secondary coil, we can use the transformer turns ratio formula:
Voltage_ratio = Ns / Np
Plugging in the given values, we get:
Voltage_ratio = 953,677 / 739 = 1291.862
Now, we can calculate the voltage in the secondary coil using the formula:
Voltage_secondary = Voltage_ratio * Voltage_primary
Plugging in the values, we get:
Voltage_secondary = 1291.862 * 58 V = 74843.004 V
Therefore, the voltage in the secondary coil is approximately 74843 V.
d.) To calculate the current in the secondary coil, we can use the power formula:
Power = Voltage * Current
Since the power of the secondary coil is the same as the power of the primary coil, we can use the values we previously calculated for the power (4408 W) and the secondary voltage (74843 V) to find the current in the secondary coil.
Rearranging the formula, we get:
Current_secondary = Power / Voltage_secondary
Plugging in the values, we get:
Current_secondary = 4408 W / 74843 V ≈ 0.059 A
Therefore, the current in the secondary coil is approximately 0.059 A.