Create a detailed visual representation of the following scenario: A shop with various items. One of these items is marked up by a small percentage. Beside it, on a table, is a purse containing Sh 200. Additionally, there are two less items near the purse than were in the shopping bag initially. The items, money, purse, table and shopping bag should all be apparent within the image, however, the image should contain no text.

when the price of an item was increased by sh.5, i bought 2 items fewer with sh 200. what is the current price of the item?

current price ---- x

increased price ---- x+5

200/x - 200/(x+5) = 2
Solve for x, reject the negative answer.
I suggest you multiply each term by x(x+5) to get the quadratic

Let the original price of the item be x

New price of the item be x+5
Then:
200/x -200/x+5 =2
200(x+5) -200x =2x(x+5)
200x + 1000 -200x =2x^2 +10x
2x^2 +10x-1000 =0
x^2 +5x -500=0
Product= -500
Sum =5
(25,-20)
x^2 +25x -20x -500 =0
x(x +25) -20(x+25) =0
x-20 =0
x=20
Or
X+25 =0
x= -25
Since the price cannot be a negative we take the positive value therefore the final answer is 20

the final answer is 25

current price is (x+5)=(20+5)

Very wrong please make a video

Very nice

Very nice

I dont really understand

Very good 😊

i underatood✌

Let the original price of an item be

x
Let the number of items be y
(x+5)(y-2)=200...(i)
xy=200..(ii)
y=200/x..(iii)
From (i)
xy-2x+5y-10=200..(iv)
Substitute (iii) in (iv)
x(200/x)-2x+1000/x-210=0
200-210-2x+1000/x=0
-10-2x+1000/x=0
-10x-2x²+1000=0
x²+5x-500=0
x²+25x-20x-500=0
x(x+25)-20(x+25)=0
(x-20)(x+25)=0
But x≠-25 since x>0
Therefore
x=sh 20
y=200/20=10 items