Two planes leave an airport flying at the same rate.If the first plane flies 1.5 hours longer than the second plane and travels 2700 miles while the second plane travels only 2025 miles,
for how long was each plane flying?
Let their rate be x mph
time for first = 2700/x
time for second = 2025/x
2700/x - 2025/x = 1.5
times x
2700 - 2025 = 1.5x
x = 450
so the first flew for 2700/450 hrs or 6 hrs
a nd the 2nd flew for 2025/450 or 4.5 hrs
notice the difference is 1.5 hrs
rate=distance/time
2700/*=2025/y
2700/*=2025/*-1.5,
*diferent from 0,1.5
*=6hrs & y=4.5hrs
Thank You! and
my answer and your answer are the same
* this symbols multiply
It is just that your text came out weird.
What's with all the * symbols all over the place?
yup, that's what it means.
So what is " *diferent from 0,1.5 " and " 2700/*=2025/*-1.5, " ???
That's what I was objecting to.
excuse me
* this symbols star
Yes the answer is 6hrs& 4.5hrs exact answer
To find out the flying time for each plane, we can set up a system of equations based on the given information.
Let's assume the flying time for the second plane is "t" hours. Since the first plane flew 1.5 hours longer, its flying time can be represented as "t + 1.5" hours.
Now, we can calculate the speed at which both planes are flying. We know that speed = distance / time.
The speed of the first plane is (2700 miles) / (t + 1.5 hours), and the speed of the second plane is (2025 miles) / t hours.
Since both planes are flying at the same rate, their speeds must be equal:
(2700 miles) / (t + 1.5 hours) = (2025 miles) / t hours
To solve this equation, we can cross-multiply:
2700t = 2025(t + 1.5)
Now, let's simplify and solve for "t":
2700t = 2025t + 3037.5
675t = 3037.5
t ≈ 4.5
Therefore, the second plane flew for approximately 4.5 hours. Since the first plane flew 1.5 hours longer, its flying time is:
t + 1.5 = 4.5 + 1.5 = 6 hours
So, the first plane flew for 6 hours, and the second plane flew for 4.5 hours.