What volume of 0.100 M K2S solution contains 3.5 g of the solute?
mols solute(K2S) = grams/molar mass = ?
Then M = mols/L. You know M and mols, solve for L.
Post your work if you get stuck.
To find the volume of the K2S solution containing 3.5 g of the solute, we need to use the equation:
molarity (M) = moles of solute (n) / volume of solution (V)
First, let's calculate the number of moles of solute (K2S):
molar mass of K2S = 39.10 g/mol (for K) + 32.07 g/mol (for S) = 71.17 g/mol
moles of K2S = mass of solute / molar mass of K2S
= 3.5 g / 71.17 g/mol
≈ 0.049 moles of K2S
Now we can rearrange the equation to solve for the volume of the solution (V):
V = n / M
V = 0.049 moles / 0.100 moles/L
≈ 0.49 L
Therefore, the volume of the 0.100 M K2S solution containing 3.5 g of the solute is approximately 0.49 L.
To find the volume of 0.100 M K2S solution that contains 3.5 g of the solute, you need to use the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
First, calculate the moles of K2S using the given mass and the molar mass of K2S. The molar mass of K2S is calculated by summing the atomic masses of potassium (K) and sulfur (S):
Molar mass of K2S = (2 * atomic mass of K) + atomic mass of S
The atomic masses of K and S can be found from the periodic table. Once you have the molar mass of K2S, use it to calculate the moles of K2S:
moles of K2S = mass of K2S / molar mass of K2S
Next, rearrange the equation for molarity to solve for volume:
volume of solution (in liters) = moles of solute / Molarity
Now you can plug in the values to calculate the volume of the K2S solution:
volume of solution (in liters) = moles of K2S / Molarity
Remember to convert the grams of K2S to moles before making this calculation.