9. John Goodman weighs 250 pounds, so he decides to go on a diet. At the end of the first week, he weighs 240. Then at the end of the second week, he weighs 230.

Fill in the blanks of the arithmetic formula [ A(n) = d + a1(n – 1) ] for this scenario.

A(n) = _____ + _____ (10– 1 )
How much will he weigh at the end of week 12? ___

What don't you understand?

im not sure what numbers i should fill in the blanks with

A(n) = __x___ + __x__ (n– 1 )
250, 140? idk
should n be 10?
(10-1)

when n = 0 (now) weight is 250

when n = 1, weight is 240 -----> 250 - 1(10)
when n = 2 weight = 230 -------> 250 - 2(10)
....
when n = n, weight = 250 - 10n

I don't know about the A(n) = d + a1(n – 1)
usually d is reserved to represent the common difference, which in
this case would be 10, a1 usually is the first term

To fill in the blanks of the arithmetic formula [A(n) = d + a1(n – 1)] for this scenario, we need the value of 'd' and 'a1'.

In this case, 'd' represents the initial weight of John Goodman, which is 250 pounds.
To find 'a1', we need to calculate the common difference in weight lost each week. In this scenario, John Goodman lost 10 pounds each week. Therefore, 'a1' is 10 pounds.

Now we can fill in the blanks of the arithmetic formula:

A(n) = 250 + 10 * (n – 1)

To calculate how much John Goodman will weigh at the end of week 12, we need to substitute the value of 'n' as 12 into the formula:

A(12) = 250 + 10 * (12 – 1)
A(12) = 250 + 10 * 11
A(12) = 250 + 110
A(12) = 360

Therefore, John Goodman will weigh 360 pounds at the end of week 12.