Calculate the values of a,A and C in triangle ABC ,given that b=17.23cm, c=10.86cm and B= 101°15'
I don't understand
I don't really understand all of them
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sinC/c = sinB/B
sinC/10.86 = sin 101°15'/17.23
so, C=38°11'
now you can get A = 180°-(B+C)
then a/sinA = b/sinB