An isosceles right triangle has legs of equal length. If the hypotenuse is 22 inches long, find the length of each leg. Please help me on this problem so bad!!! I NEED AN ANSWER TO THIS PROBLEM IMMEDIATELY!!!! :(
In a right triangle, square on the hypotenuse is equal to sum of the squares on the other two sides.
Here, other two sides as it is an isosceles right triangle.
Let these sides be each x inches.
x² + x² = 22²
2 x² = 484
Divide both sides by 2
x² = 242
x² = 121 ∙ 2
x = √ 121 ∙ √2
x = 11 √2 in
In a right triangle, square on the hypotenuse is equal to sum of the squares on the other two sides.
Here, other two sides as it is an isosceles right triangle.
Let these sides be each x inches.
x² + x² = 22²
2 x² = 484
Divide both sides by 2
x² = 242
x² = 121 ∙ 2
x = √ 121 ∙ √2
x = 11 √2 in
same
What does gY even mean??? Your not even helping at all!!! ;(
Oh dear, I can see you're in quite a "tri-angle" with this problem. But don't worry, I'm here to help you out with some humor!
Since it's an isosceles right triangle, we know that the legs are equal in length. Let's call the length of each leg "x". Now, according to Pythagoras, the hypotenuse squared is equal to the sum of the squares of the other two sides.
So we have the equation: x^2 + x^2 = 22^2
Simplifying that, we get: 2x^2 = 484
Now, let's solve this equation to find the length of each leg:
x^2 = 484/2
x^2 = 242
Taking the square root of both sides, we find that:
x ≈ 15.56
So each leg of the isosceles right triangle is approximately 15.56 inches long. Keep in mind, I can't guarantee these measurements will come out "perfectly," but I hope they put a smile on your face!
To find the length of each leg of an isosceles right triangle, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, let's call the length of each leg "x". So, according to the Pythagorean theorem:
x^2 + x^2 = 22^2
Simplifying the equation, we have:
2x^2 = 484
Dividing both sides of the equation by 2:
x^2 = 242
Taking the square root of both sides to solve for x:
x = √242
Therefore, the length of each leg of the isosceles right triangle is √242 inches.