The expression ((7x+14)(4x-4))/((x+2)(x-1)) can be simplified to an integer value.
What is the quotient after canceling common factors and simplifying?
Can someone show me how to do this problem?
((7x+14)(4x-4))/((x+2)(x-1))
(7(x+2)*4(x-1))/((x+2)(x-1))
7*4 = 28
Thank you :)
To simplify the expression ((7x+14)(4x-4))/((x+2)(x-1)), we can start by canceling any common factors in the numerator and denominator.
Let's start by factoring the expressions:
7x + 14 can be factored as 7(x + 2)
4x - 4 can be factored as 4(x - 1)
Substituting these factorizations into the numerator, we get:
((7x+14)(4x-4)) = (7(x+2))(4(x-1))
Next, we can factor the denominator:
x + 2 remains the same
x - 1 remains the same
Using these factorizations, we can rewrite the expression as follows:
((7(x+2))(4(x-1)))/((x+2)(x-1))
Now, we can cancel out the common factors in the numerator and denominator, which are (x + 2) and (x - 1):
((7(1))(4))/((1))
Simplifying further, we have:
(28)/(1) = 28
Therefore, the quotient of the expression ((7x+14)(4x-4))/((x+2)(x-1)) after canceling common factors and simplifying is 28.