What is the temperature in Celcius of 3.33 moles of neon that occupies 13.4 liters under the pressure of 3 atmospheres.
p v = n r t
be sure to choose the correct units for r
convert ºK to ºC
And learn to spell celsius correctly.
To find the temperature in Celsius, we need to use the ideal gas law equation:
PV = nRT
where:
P = pressure (in atmospheres)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
First, we need to convert the given pressure of 3 atmospheres to Pascals (Pa), as the ideal gas constant is usually defined in terms of Pascals. 1 atmosphere is approximately equal to 101,325 Pascals.
So, the pressure in Pascals will be 3 atmospheres * 101,325 Pa/atmosphere = 303,975 Pa.
Next, we can rearrange the equation to solve for temperature (T):
T = PV / (nR)
Plugging in the given values:
P = 303,975 Pa
V = 13.4 liters
n = 3.33 moles
R = 0.0821 L·atm/(mol·K)
T = (303,975 Pa) * (13.4 liters) / (3.33 moles * 0.0821 L·atm/(mol·K))
Now, we can simplify the equation:
T = (303,975 Pa * 13.4 liters) / (3.33 moles * 0.0821 L·atm/(mol·K))
T = (4,073,065 Pa·liters) / (0.27273 moles·L·atm/K)
T ≈ 14,941,476.77 K
Since the answer is in Kelvin, we can convert it to Celsius by subtracting 273.15 from the Kelvin temperature:
Temp in Celsius = 14,941,476.77 K - 273.15 K
Temp in Celsius ≈ 14,941,203.62°C
Therefore, the temperature of 3.33 moles of neon that occupies 13.4 liters under the pressure of 3 atmospheres is approximately 14,941,203.62°C.