What will be the value of x in the equation 4x^2 - x = 0?
A. 1
B. 4
C. 0 , 1 / 4
D. 18
----------------------------------------------------------------------------------------------------4x^2 - x = 0
4x^2 - x + x = 0 + x
4x^2 = x
I'm not sure what to do from this point on
4x^2 - x = 0 is what the first step is supposed to be. My apologies.
4x^2 - x = 0
x(4x - 1) = 0
x = 0 OR 4x - 1 = 0
x = 0 or x = 1/4
Thank you for your feedback, Reiny. Much appreciated.
To solve the equation 4x^2 - x = 0, you can use the quadratic formula or factor the equation.
Using the quadratic formula:
The quadratic formula is given by x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.
In this case, a = 4, b = -1, and c = 0. Plugging these values into the quadratic formula, we get:
x = (1 ± √((-1)^2 - 4 * 4 * 0)) / (2 * 4)
x = (1 ± √(1 - 0)) / 8
x = (1 ± 1) / 8
Therefore, the possible values of x are:
x = (1 + 1) / 8 = 2/8 = 1/4
x = (1 - 1) / 8 = 0/8 = 0
So the answer is C. 0, 1/4.