Find each of the following zeros f(y)=y^5-2y^3+y
1,-1
Good
To find the zeros of the function f(y) = y^5 - 2y^3 + y, we need to solve the equation f(y) = 0.
Step 1: Set the equation equal to zero:
y^5 - 2y^3 + y = 0
Step 2: Factor out common terms, if possible:
y(y^4 - 2y^2 + 1) = 0
Step 3: Factor the expression inside the parentheses:
y(y^2 - 1)^2 = 0
Step 4: Apply the zero product property, which states that if a product of factors is equal to zero, then at least one of the factors must be zero. In this case, we have two factors: y and (y^2 - 1).
Set each factor equal to zero and solve for y.
Factor 1:
y = 0
Factor 2:
y^2 - 1 = 0
Solving for y^2 - 1 = 0:
y^2 = 1
Taking the square root of both sides:
y = ±√1
Therefore, the zeros of f(y) = y^5 - 2y^3 + y are y = 0, y = 1, and y = -1.
f(y)=y^5-2y^3+y;find zeros
y^5-2y^3+y = 0
y(y^4-2y^2+1) = 0
y(y^2-1)^2 = 0
y (y-1)^2 (y+1)^2 = 0
got it now?