A body of mass 100kg is released from a height of 200m .with what energy does the body strikes the ground (take g=10m/s)
I ask you
what is mass*g*height?
How can i find the answer
Yes
ONYEKACHI
HEIGH
HIGH
YES
BY GOD
To calculate the energy with which the body strikes the ground, we need to consider its potential energy at the top (initial height) and its kinetic energy at the bottom. We can use the law of conservation of energy, which states that energy is neither created nor destroyed, only transferred or transformed from one form to another.
1. Calculate the potential energy at the top:
Potential energy (PE) = Mass (m) × Gravitational acceleration (g) × Height (h)
In this case, the mass (m) is given as 100 kg, the gravitational acceleration (g) is given as 10 m/s², and the height (h) is given as 200 m.
PE = 100 kg × 10 m/s² × 200 m
PE = 200,000 joules (J)
2. Calculate the kinetic energy at the bottom:
Kinetic energy (KE) = 1/2 × Mass (m) × Velocity squared (v²)
Since the body is initially at rest, there is no initial velocity (v), but when it reaches the bottom, it will have a final velocity.
To find the final velocity, we can use the equation:
v = √(2gh)
v = √(2 × 10 m/s² × 200 m)
v ≈ 63.25 m/s
Now, we can calculate the kinetic energy (KE):
KE = 1/2 × 100 kg × (63.25 m/s)²
KE ≈ 200,656.25 J
3. Add the potential energy and kinetic energy:
The total energy (TE) with which the body strikes the ground is the sum of its potential energy and kinetic energy.
TE = PE + KE
TE = 200,000 J + 200,656.25 J
TE ≈ 400,656.25 J
Therefore, the body strikes the ground with approximately 400,656.25 joules (J) of energy.