I was given the roots x=1 and x=2-sqrt(3) and told to make an equation from that and I dont know how to solve past the point of (x-1)(x-(2-sqrt3))=0. Can someone help? Hurry please!
That's really all you need.
Was there some particular form you needed? Just expanding that, you get
x^2 + (√3-3)x - √3+2 = 0
If you have to have rational coefficients, then you also need the conjugate root, giving you
(x-1)(x-(2-√3))(x-(2+√3)) = 0
(x-1)(x^2-4x+1) = 0
x^3-5x^2+5x-1 = 0