A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of gas would result if the pressure was 0.5 atm?
PV=kT
since T is constant, kT is constant, and so is PV.
so, you want V such that
0.5*V = 0.8*3.5
Why did the gas go to therapy? It had too much pressure and needed to vent out its problems!
Now, back to your question. We can use Boyle's Law to solve this. Boyle's Law states that the volume of a gas is inversely proportional to its pressure, assuming the temperature remains constant.
So, we can set up a proportion:
V1/P1 = V2/P2
Where V1 is the initial volume (3.5 L), P1 is the initial pressure (0.8 atm), V2 is the final volume (which we need to find), and P2 is the final pressure (0.5 atm).
Plugging in the values:
3.5 L / 0.8 atm = V2 / 0.5 atm
Cross-multiplying:
0.8 atm * V2 = 3.5 L * 0.5 atm
Dividing both sides by 0.8 atm:
V2 = (3.5 L * 0.5 atm) / 0.8 atm
V2 = 2.1875 L
So, if the pressure was 0.5 atm, the volume of the gas would be approximately 2.1875 L. But be careful not to "inflate" this answer!
To determine the volume of gas when the pressure changes, we can use Boyle's Law which states that the pressure of a gas is inversely proportional to its volume at constant temperature.
The formula for Boyle's Law is:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure
V2 = Final volume
Let's plug in the given values:
P1 = 0.8 atm
V1 = 3.5 L
P2 = 0.5 atm
Using the formula, we can rearrange it to solve for V2:
V2 = (P1 * V1) / P2
Now, substitute the values:
V2 = (0.8 atm * 3.5 L) / 0.5 atm
V2 = 2.8 L
Therefore, the final volume of the gas would be 2.8 L if the pressure was 0.5 atm while the temperature remains constant.
To determine the volume of gas at a different pressure, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to its pressure, assuming the temperature remains constant.
Boyle's Law equation:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure (0.5 atm in this case)
V2 = final volume (unknown)
First, let's plug in the given values:
P1 = 0.8 atm
V1 = 3.5 L
P2 = 0.5 atm
Now we can rearrange the equation to solve for V2:
V2 = (P1 * V1) / P2
Substituting the values:
V2 = (0.8 atm * 3.5 L) / 0.5 atm
V2 = 2.8 L
Therefore, if the pressure of the gas is reduced to 0.5 atm while keeping the temperature constant, the volume of the gas would be 2.8 L.