A student collected nitrogen by displacing water in a graduated cylinder. the atmospheric pressure was 738.9 mmhg; the height of the water remaining in the cylinder was 13.2 mm; the partial pressure of the water was 18.8 mmhg. determine the partial pressure of the nitrogen in the cylinder. the density of mercury is 13.6 g/m

Question

A student collected nitrogen by displacing water in a graduated cylinder. the atmospheric pressure was 738.9 mmhg; the height of the water remaining in the cylinder was 13.2 mm; the partial pressure of the water was 18.8 mmhg. determine the partial pressure of the nitrogen in the cylinder. the density of mercury is 13.6 g/m

Answer 1

pressureN2=738.9-(13.2/13.9)mmHg-18.8mmHg

Answer 2

To determine the partial pressure of nitrogen in the cylinder, we need to use Dalton's Law of Partial Pressures. According to this law, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each gas.

In this case, we know that the atmospheric pressure is 738.9 mmHg, and the partial pressure of water is 18.8 mmHg. We need to find the partial pressure of nitrogen.

First, we need to calculate the partial pressure of the gas that is displaced by the water. Since water displaces the gas, the pressure exerted by the water column is equal to the partial pressure of the displaced gas.

The height of the water remaining in the cylinder is given as 13.2 mm. We can use this information to calculate the pressure exerted by the water column using the formula P = ρgh, where P is pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the height of the liquid column.

Given that the density of mercury is 13.6 g/mL (note: you mentioned density in g/m, but it should be g/mL for mercury), we can convert it to g/mm^3 by dividing by 1000. Thus, the density of mercury is 0.0136 g/mm^3.

Plugging in the values, we have P = (0.0136 g/mm^3)(13.2 mm)(9.8 m/s^2). Note that we have to convert mm to m by dividing by 1000.

P = (0.0136 g/mm^3)(0.0132 m)(9.8 m/s^2) = 0.0174 g/mm^2/s^2

Now, we have the pressure exerted by the water column, which is equivalent to the partial pressure of the displaced gas.
So the partial pressure of the displaced gas is 0.0174 g/mm^2/s^2.

Since the partial pressure of the displaced gas is equal to the partial pressure of nitrogen, we can conclude that the partial pressure of nitrogen in the cylinder is 0.0174 mmHg.