an equilateral triangle of 20cm is inscribed in a circle calculate the distance of a side of a triangle from the center of the circle

20/√3

sorry. That is the radius.

the distance is just the altitude minus that radius, right?

An equilateral triangle of side 20cm is inscribe in a circle. calculate the distance of the side of the triangle from the centre of the circle

Pls answer this question

To calculate the distance of a side of an equilateral triangle from the center of the circle, we can use the properties of an equilateral triangle and the relationship between the side length of the equilateral triangle and the radius of the circle it is inscribed in.

In an equilateral triangle, all sides are equal and all angles are 60 degrees. The center of the circle is also the circumcenter of the equilateral triangle, which means it is equidistant from all the vertices of the triangle.

Let's denote the distance from the center of the circle to a side of the triangle as 'd'. The distance from the center to the vertex of the triangle would then be 'd' + 'r', where 'r' is the radius of the circle.

In an equilateral triangle, the distance from the vertex to the center is one-third of the height of the triangle. The height of an equilateral triangle can be found using the formula h = (sqrt(3) / 2) * s, where 'h' is the height and 's' is the side length.

Given that the side length of the triangle is 20 cm, we can find the height as h = (sqrt(3) / 2) * 20 cm = 10 * sqrt(3) cm.

Since the distance from the center to the side is one-third of the height, we can calculate 'd' as d = (1/3) * 10 * sqrt(3) cm = 10/3 * sqrt(3) cm.

Therefore, the distance of a side of the equilateral triangle from the center of the circle is 10/3 * sqrt(3) cm.